subject
Physics, 14.02.2023 15:50 myparentsrock17

A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they

Answers

ansver
Answer from: rosemary909

The expression for the gravitational force between two bodies is given by:

F=G\frac{m_1m_2}{r^2}

where,

G: Cavendish's constant = 6.67*10-11Nm^2/kg^2

m1 = 3.0kg

m2 = 14kg

Solve the equation above for r:

\begin{gathered} r=\sqrt{\frac{Gm_1m_2}{F}} \\ r=\sqrt[]{\frac{(6.67\cdot10^{-11}\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^{-10}N}} \\ r\approx1.67m \end{gathered}

Hence, the distance between the dog and the car is approximately 1.67m

ansver
Answer from: Quest
Which principle states: "geologic processes taking place on earth today operated similarly in the past and can be used to explain past geologic events"? a. lateral continuity
ansver
Answer from: Quest
Golf is for old men who smell

Other questions on the subject: Physics

image
Physics, 21.06.2019 13:00, nepats222
The differences between  a compression wave and a transverse wave?
Answers: 1
image
Physics, 22.06.2019 08:30, katarawho
Abike rider starts from rest and accelerates 28.0 meters down a slope in 5.00 seconds. what is her acceleration? select one: a. 3.21 m/sec2 b. 1.75 m/sec2 c. 9.80 m/sec2 d. 2.24 m/sec2
Answers: 3
image
Physics, 22.06.2019 13:30, ferrin6507
Place me with this question is my last question
Answers: 3
image
Physics, 22.06.2019 19:30, QueenNerdy889
Refrigerant-134a flows through a carnot heat pump cycle at 0.5 kg/s. it is known that the maximum absolute temperature in the cycle is 1.1 times the minimum absolute temperature, and the net power input to the cycle is 2.5 kw. if the refrigerant changes from a saturated vapor to a saturated liquid during the heat rejection process, determine the maximum magnitude of the enthalpy of vaporization for this process in kj/kg (with 3 significant figures).
Answers: 3
You know the right answer?
A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far...

Questions in other subjects: