a parallel-plate capacitor has a capacitance of 10 mf and is charged with a 20-v power supply. the power supply is then removed and a dielectric material of dielectric constant 4.0 is used to fill the space between the plates. what is the voltage now across the capacitor?

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

are there answer choices to this question? this seems like a question where you have options to choose from.

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