Physics, 07.06.2020 00:04 samantaisabel6015
Zad. 1. Jaką pracę wykona dźwig, który pracował przez 1,5 h napędzany silnikiem o mocy 200 kW?
Zad. 2 Jaką moc ma ciało pokonujące siłę 300N na drodze 2,5m w ciągu 0,5 min?
Zad. 3 Przez jaki czas traktor, który orze w polu, o silniku z mocą 100 kW wykona pracę 10 MJ?
SZYBKO!
Answer from: achewitt3965
Explanation:
1) Moc to wskaźnik czasu pracy w stosunku do czasu.
Moc = czas pracy / czas
Czas pracy = moc * czas
Podana moc = 200 kW = 200 000 Watów
Czas = 1,5 godziny = 1,5 * 3600 = 5400 sekund
workdone = 200 000/5400
Obróbka = 37,04 dżula
2) Moc = Gotowe / czas
Od zakończenia = Siła * Odległość
Moc = siła * Odległość / czas
Podana siła = 300 N.
Odległość = 2,5 m
czas = 0,5 min = 0,5 * 60 = 30 sekund
Moc = 300 * 2,5 / 30
Moc = 25 watów
3) Moc = Gotowe / czas
Czas potrzebny = praca / moc
Biorąc pod uwagę pracę wykonaną przez ciągnik = 10 MJ = 10 * 10 ^ 6 Dżuli
Moc = 100 kW = 100 000 watów
Czas wzięty = 10 ^ 7/10 ^ 5
Zajęty czas = 100 sekund
Answer from: Quest
135 peaches were sold.
Answer from: Quest
Your answer is 1.5 hope i
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Zad. 1. Jaką pracę wykona dźwig, który pracował przez 1,5 h napędzany silnikiem o mocy 200 kW?
Zad....
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