A particular planet has a moment of inertia of 8.26 × 10^(36) kg⋅m^2 and a mass of 6.54 × 10^22 kg. Based on these values, what is the planet's radius? Hint: Because planets are the shape of a sphere, the moment of inertia is I = (2/5)mr^2.
1.776933x10^7
Explanation:
Moment of inertia I = 8.26x10^36kgm^2
Mass of planet m = 6.54x10^22kg
Also, Planet is solid sphere so that, Moment of inertia is I = _2_ m
R^2= 0.4 R^2 5
Where R is radius of planet
Putting into calculation
We get,
I = _2_ m R^2
5
8.26x10^36 = 0.4x6.54x10^22xR^2
8.26x10^14 = 2.616 R^2
R = 1.776933x10^7
close lines strong magnet less close weaker
the answer is ampere
the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.