Two loudspeakers are placed on a wall 2 m apart. A listener stands directly in front of one of the speakers, 81.7 m from the wall. The speakers are being driven by the same electric signal generated by a harmonic oscillator of frequency 4450 Hz. What is the phase difference ∆Φ between the two waves (generated by each speaker) when they reach the listener? The speed of the sound in air is 343 m/s. Answer in units of rad.
The phase difference is
Explanation:
From the question we are told that
The distance between the loudspeakers is
The distance of the listener from the wall
The frequency of the loudspeakers is
The velocity of sound is
The path difference of the sound wave that is getting to the listener is mathematically represented as
Substituting values
The phase difference is mathematically represented as
=
Where is the wavelength which is mathematically represented as
substituting value
Substituting value into the equation for phase difference
=
i would think it's food chain
the answer is 100. i just did this lesson and got a 100% on it. : )
-fishtank