An engine flywheel initially rotates counterclockwise at 6.69 rotations/s. Then, during 20.1 s , its rotation rate changes to 2.65 rotations/s clockwise. Find the flywheel's average angular acceleration (including its sign) in radians per second squared. Define counterclockwise rotation as positive.
Answer from: tbeck225
Explanation:
Given that
We are told to assume counterclockwise to be positive
Then, clockwise will be negative
initial angular velocity counterclockwise
ωi = 6.69 rotation/sec
1 rotation = 1 revolution = 2π rad
Then, ωi = 6.69 × 2π rad/s
ωi = 42.03 rad/s
Final angular velocity clockwise
ωf = 2.65 rotation/sec
ωf = 2.65 × 2π rad/s
ωf = —16.65 rad/s
Time taken t = 20.1s
Now, we want to find angular acceleration, α
Angular acceleration is given as
α = ∆ω/∆t
α = (ωf — ωi) / t
α = (—16.65—42.03) / 20.1
α = —58.68 / 20.1
α = —2.92 rad/s²
So, the angular acceleration is —2.92 rad/s²
Answer from: Quest
i think its c if i'm wrong
Answer from: Quest
Answer form flower;
Physics, 22.06.2019 00:00, anna40794
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