Physics, 02.01.2020 20:31 haileycrane

What are the charge and the charge density on the surface of a conducting sphere of radius 0.15 m whose potantial is 200v?

Answers

Answer from: josh7049

The charge and the charge density on the surface of a conducting sphere is $3.34\times 10^{-9}\ C$ and $1.18\times 10^{-8}\ C/m^2$ respectively.

Explanation:

It is given that,

Radius of the conducting sphere, r = 0.15 m

Potential, V = 200 V

Potential on the surface of sphere is given by :

$V=\dfrac{kq}{r}$

q is the charge on the sphere

$q=\dfrac{Vr}{k}$

$q=\dfrac{200\times 0.15}{9\times 10^9}$

$q=3.34\times 10^{-9}\ C$

Charge per unit area is called charge density on the surface. it is given by :

$\sigma=\dfrac{q}{A}$

$\sigma=\dfrac{q}{4\pi r^2}$

$\sigma=\dfrac{3.34\times 10^{-9}}{4\pi (0.15)^2}$

$\sigma=1.18\times 10^{-8}\ C/m^2$

So, the charge and the charge density on the surface of a conducting sphere is $3.34\times 10^{-9}\ C$ and $1.18\times 10^{-8}\ C/m^2$ respectively. Hence, this is the required solution.

Answer from: Quest

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

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What are the charge and the charge density on the surface of a conducting sphere of radius 0.15 m wh...