Aspectral line from a star is observed to have a wavelength of 656.5 nm. the rest wavelength of this line is 656.8 nm. (a) what is the speed of the star, and (b) is it approaching or receding from the earth? (c) if the star’s emitted wavelength is the same as the rest value, what is happening?
speed of star is 1.37 × m/s
it is approaching to earth because wavelength of star is decreasing than rest
if emit same wavelength it does not move anywhere
it will remain steady condition with respect earth
Explanation:
given data
wavelength = 656.5 nm
rest wavelength = 656.8 nm
to find out
the speed of the star , is it approaching
solution
we know here equation that is
wavelength shift / wavelength at rest = velocity of source / speed of light
so put all value and find
velocity of source = 3 × × 3 × / 656.8 ×
velocity of source star = 1.37 × m/s
and
it is approaching to earth because wavelength of star is decreasing than rest
and
if emit same wavelength it does not move anywhere
it will remain steady condition with respect earth
cell differentiation is how generic embryonic cells become specialized cells. this occurs through a process called gene expression. gene expression is the specific combination of genes that are turned on or off (expressed or repressed), and this is what dictates how a cell functions.
explanation: