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Mathematics, 25.07.2019 03:50 sammybrain

Aparticle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. what is the maximum height of the particle? 100 feet 96 feet 60 feet 56 feet

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Answer from: Bamaboy8804

The maximum height of the particle is 100 ft

A is correct

Step-by-step explanation:

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second.

The standard equation of parabolic projectile.

h(t)=-16t^2+v_0t+h_0

where,

v_0=16\ ft/s

h_0=96\ ft

h(t)=-16t^2+16t+96

So, we get the parabolic equation of path.

The maximum value at vertex.

t=-\dfrac{b}{2a}

t=-\dfrac{16}{-32}=\dfrac{1}{2}

Maximum at t=0.5

h(0.5)=-16(0.5)^2+16(0.5)+96

h(0.5)=100

Hence, The maximum height of the particle is 100 ft

ansver
Answer from: Quest

step-by-step explanation:

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ansver
Answer from: Quest

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour = (1/1000)/(1/3600)=3600/1000=18/5=3.6 kilometer/hour

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second= 15*3.6=54 kilometer/hour   which is the required answer.

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