Mathematics, 30.06.2019 17:00 wiredq2049
Now suppose the roster has 5 guards, 5 forwards, 3 centers, and 2 "swing players" (x and y) who can play either guard or forward. if 5 of the 15 players are randomly selected, what is the probability that they constitute a legitimate starting lineup
Answer from: carlosthenoob03
Given that a starting lineup in basketball consists of two guards, two forwards,
and a center. Suppose the roster has 5 guards, 5 forwards, 3 centers,
and 2 "swing players" (X and Y) who can play either guard or forward. If
5 of the 15 players are randomly selected, what is the probability that
they constitute a legitimate starting lineup?
The possible selections are as follows:
No swing player is selected: 5C2 x 5C2 x 3C1 = 10 x 10 x 3 = 300
One swing is selected as a guard: 5C1 x 2C1 x 5C2 x 3C1 = 5 x 2 x 10 x 3 = 300
One swing is selected as a forward: 5C1 x 2C1 x 5C2 x 3C1 = 5 x 2 x 10 x 3 = 300
One swing is selected as a guard and the other as a forward: 5C1 x 2C1 x 1C1 x 5C1 x 3C1 = 5 x 2 x 5 x 3 = 150
Two swings is selected as guards: 5C0 x 2C2 x 5C2 x 3C1 = 1 x 1 x 10 x 3 = 30
Two swings is selected as forwards: 5C0 x 2C2 x 5C2 x 3C1 = 1 x 1 x 10 x 3 = 30
Number of legitimate ways = 300 + 300 + 300 + 150 + 30 + 30 = 1110
Total number of ways = 15C5 = 3003
Therefore, probability of legitimate team = 1110 / 3003 = 0.37 or 37%.
The possible selections are as follows:
No swing player is selected: 5C2 x 5C2 x 3C1 = 10 x 10 x 3 = 300
One swing is selected as a guard: 5C1 x 2C1 x 5C2 x 3C1 = 5 x 2 x 10 x 3 = 300
One swing is selected as a forward: 5C1 x 2C1 x 5C2 x 3C1 = 5 x 2 x 10 x 3 = 300
One swing is selected as a guard and the other as a forward: 5C1 x 2C1 x 1C1 x 5C1 x 3C1 = 5 x 2 x 5 x 3 = 150
Two swings is selected as guards: 5C0 x 2C2 x 5C2 x 3C1 = 1 x 1 x 10 x 3 = 30
Two swings is selected as forwards: 5C0 x 2C2 x 5C2 x 3C1 = 1 x 1 x 10 x 3 = 30
Number of legitimate ways = 300 + 300 + 300 + 150 + 30 + 30 = 1110
Total number of ways = 15C5 = 3003
Therefore, probability of legitimate team = 1110 / 3003 = 0.37 or 37%.
Answer from: Quest
11) obtuse
13)right
15) acute
Answer from: Quest
depends what are you allowed to do ?
Mathematics, 21.06.2019 18:00, cgonzalez1371
Janie has $3. she earns $1.20 for each chore she does and can do fractions of chores. she wants to earn enough money to buy a cd for $13.50. write an inequality to determine the number of chores, c, janie could do to have enough money to buy the cd.
Answers: 2
Mathematics, 21.06.2019 19:30, mary9590
Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.
Answers: 3
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