Mathematics, 21.01.2022 18:20 mercydiaz84

Find the dy/dx

y= sin²x/cos²x

Find the dy/dxy= sin²x/cos²x

Answers

Answer from: karissanichole18

d y dx=0

Explanation:

From the given

y=sin2x+cos2x

The right side of the equation is

y=1

d y d x=d d x(1)=0

or we can do it this way.

y = sin2x+cos2x

d y d x=2

⋅(sinx)2−1

⋅

d d x(sinx)+2

(cosx)2−1 d d x(cosx)

d y d x=2⋅

sinx⋅cosx+2⋅cosx⋅(−sinx)

dydx=2⋅sinx⋅cosx−2⋅sinx⋅cosx

dydx=0

God blessI hope the explanation is useful.

Answer from: Quest

the image of (6, 9) under a dilation is (4, 6). the scale factor is

b. 2/3

Answer from: Quest

40% off the regular price is the correct answer.

step-by-step explanation:

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Find the dy/dx

y= sin²x/cos²x
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