Mathematics, 18.09.2021 14:00 rhaquan66766

Where is the hole for the following function located? f(x) = x+3/(x-4)(x+3)
A. x= -3
B. y=-3
C. x= 3
D. y = 3

Answers

It would seem to be a good idea to cancel the (x + 3) factors to get f(x) = 1/(x - 4)
This is a hyperbolic graph with a vertical asymptote at x = 4.
However when x = -3 the factor (x + 3) = 0 so cannot be cancelled at this point. 0/0 is undefined.
The graph is drawn leaving a hole in the line at x = -3
The limits as we approach x = -3 from above or below that point get closer and closer to -1/7

The correct answer is A

Answer from: Quest

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.

hope this .

Answer from: Quest

answer: 8

step-by-step explanation: if you add the possibilities 5 different flavor and 3 different sizes 5+3=8

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Where is the hole for the following function located? f(x) = x+3/(x-4)(x+3)
A. x= -3
B...