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Mathematics, 25.07.2021 01:00 elizabethg56

If a sine curve has a vertical shift down 19 units with an amplitude of 21, what will the minimum and maximum values be? (i. e. how high and low will the graph go?) Min Value:
Max Value:

Answers

ansver
Answer from: andybiersack154

Given:

Amplitude = 21

Vertical shift = 19 units down

To find:

The maximum and the minimum value.

Solution:

The general form of sine function is:

y=A\sin (Bx+C)+D

Where, |A| is amplitude, \dfrac{2\pi}{B} is period, -\dfrac{C}{B} is phase shift and D is the vertical shift.

Here,

Maximum=D+A

Minimum=D-A

We have,

Amplitude: A = 21

Vertical shift: D=-19

Negative sign means shifts downwards.

Now,

Maximum=D+A

Maximum=-19+21

Maximum=2

And,

Minimum=D-A

Minimum=-19-21

Minimum=-40

Therefore, the minimum value is -40 and the maximum value is 2.

ansver
Answer from: Quest
Yess gfvtvt t t t t too many of you are not going too far away i don’t wanna was like a whole lot more stuff i gotta do you want to come home or do y’all come home
ansver
Answer from: Quest

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

\frac{2}{5}=\frac{x-18}{x}

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

\frac{2}{5}=\frac{30-18}{30}

\frac{2}{5}=\frac{12}{30}

Answer this question! eric has a riddle "i am thinking of a fraction that is equivalent to 2/5 and

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