What is the coefficient of the x^4y^3 term in the expansion of (x-2y)^7?
A. -280
B. -8
C. 560
D.35
the answer is 200
step-by-step explanation:
this is a problem about poisson probabilities. i don't know if you've
already studied poisson distributions, or if you have a place to look
to read more about the subject.
here's how you can see a poisson distribution coming. when there are
a lot of events that may happen at any time (or any place), and when
you're counting how many of them happen at a particular time (or a
particular place), and each event is independent of the others, then
the result is a poisson distribution. this is roughly true for the
chocolate chips; one chip being in a cookie has only a small effect on
the probability that another chip will be in the cookie.
once you know you have a poisson distribution, you know a lot. there
is only one parameter to a poisson distribution, so if you know the
mean, you know everything. the form of the distribution is
probability of n chips = {[e^(-x)]*(x^n)} / (n! )
answer: the correct option is d.
explanation:
it is given that the triangle j'k'l' shown on the grid below is a dilation of triangle jkl using the origin as the center of dilation.
from the given graph it is noticed that k(4,8) and k'(2,4). let origin is defined by o and scale factor is defined by k, then
(1)
distance formula,
put these values in equation (1).
therefore scale factor is and option d is correct.
B. -8
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