Mathematics, 29.11.2019 17:31 mmassaro19
Each pack of hot dogs contains 10 hot dogs (no buns), but each pack of hot dog buns contains 8 buns. phil buys a number of these packs for a barbecue. after the barbecue, phil finds that he has 4 hot dogs left over. what is the second smallest number of packs of hot dogs he could have bought?
Answer from: sustaitaj2022
Hmmm
we might need to find greatest common denomenator?
or we could just do trial and error
hmm
wait a minute
lets do this
d=number of hot dog packs
b=number of hot dog bbuns
the number of hot dogs is 4 more than the number of buns
10d=4+8b
divide both sides by 2 to make it easier
5d=2+4b
one way is to do trial and error
try values of d and find what values work for b (remember, all whole values)
if d=1, no value works for b
if d=2, b=2
that is the smallest value
keep going up
if d=3, no value works for b
if d=4, no value works for b
if d=5, no value works for b
if d=6, b=7
so 6 packs is the answer
we might need to find greatest common denomenator?
or we could just do trial and error
hmm
wait a minute
lets do this
d=number of hot dog packs
b=number of hot dog bbuns
the number of hot dogs is 4 more than the number of buns
10d=4+8b
divide both sides by 2 to make it easier
5d=2+4b
one way is to do trial and error
try values of d and find what values work for b (remember, all whole values)
if d=1, no value works for b
if d=2, b=2
that is the smallest value
keep going up
if d=3, no value works for b
if d=4, no value works for b
if d=5, no value works for b
if d=6, b=7
so 6 packs is the answer
Answer from: Quest
You're doing something i dont know how to do but search up on google slope calculator maybe that will get you there
Answer from: Quest
59/96 is the ratio hope this not 100% sure though : /
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