Mathematics, 31.10.2019 04:31 reginaldboyd28

Ineed solving for x: log x = 2.46 - 1.12 * log y

Answers

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\\\\\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)
\\\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{log cancellation rule}\\\\
-----------------------------\\\\$

$\bf log(x)=2.46-1.12log(y)\iff log_{10}(x)=2.46-1.12log_{10}(y)
\\\\\\
log_{10}(x)=2.46-log_{10}(y^{1.12})\implies log_{10}(x)+log_{10}(y^{1.12})=2.46
\\\\\\
log_{10}(x\cdot y^{1.12})=2.46\implies 10^{\cfrac{}{}log_{10}(x\cdot y^{1.12})}=10^{2.46}
\\\\\\
xy^{1.12}=10^{2.46}\implies \boxed{x=\cfrac{10^{2.46}}{y^{1.12}}}$

Answer from: Quest

Set square i think so

Answer from: Quest

20days louise can read300 pg

step-by-step explanation:

1 day 15 pg 300: 15= 20

x day 300 pg

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Ineed solving for x: log x = 2.46 - 1.12 * log y...