A ball is launched upward at 26 ft/sec from a platform that is 12 feet high. When will the ball hit the ground
9.4 seconds or 1 second
Step-by-step explanation:
From;
h = ut ± 1/2gt^2
h = 12 feet
g = acceleration due to gravity = 10 m/s^2
u = 26 ft/sec
Since it is an upward motion g is negative
12 = 26t - 5t^2
Hence;
5t^2 - 26t + 12 = 0
Solving the quadratic equation
Considering that the time taken to go up is the same time taken to hit the ground again
t = 2(4.7) seconds or t = 2(0.5) seconds
t = 9.4 seconds or 1 second
the inequality is:
250c+180g≥950
step-by-step explanation:
let c denotes the number of days in a week miyoko worked as a cryptographer.
and g denotes the number of days in a week she works as a geologist.
now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.
now miyoko's goal is to earn more than $950 this week.
hence, the inequality could be represented as:
250c+180g≥950
the graph in the attached figure
step-by-step explanation:
we have
using a graphing tool
the graph in the attached figure
the roots are ( x-intercepts) x=-0.5,x=1,x=3
the y-intercept is the point (0,3)