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Mathematics, 18.03.2021 06:20 lele142018

When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

Answers

ansver
Answer from: smartie80

omg this is pretty complicated

Step-by-step explanation:

54637$%^346*&^%vvwe

ansver
Answer from: Quest

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

ansver
Answer from: Quest

-2 is the right

Algebra semester 1 unit4 pretest linear equations

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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b...