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Mathematics, 16.11.2020 23:20 Ryan02717

The lengths of two sides of a triangle are shown. Side 1: 8x2 − 5x − 2

Side 2: 7x − x2 + 3

The perimeter of the triangle is 4x3 − 3x2 + 2x − 6.

Part A: What is the total length of the two sides, 1 and 2, of the triangle? Show your work. (4 points)

Part B: What is the length of the third side of the triangle? Show your work. (4 points)

Part C: Do the answers for Part A and Part B show that the polynomials are closed under addition and subtraction? Justify your answer. (2 points)

I hardly ever use this app, or any app like this, but this question has really got me, help please?

Answers

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Answer from: mariabarcenas6807

Part A)

7x^2+2x+1

Part B)

4x^3-10x^2-7

Part C)

Yes, they are.

Step-by-step explanation:

We are given a triangle and its two sides:

8x^2-5x-2\text{ and } 7x-x^2+3

We are also given its perimeter:

P=4x^3-3x^2+2x-6

Part A)

To find the total length of the two sides of the triangle, we can add them. So:

T=(8x^2-5x-2)+(7x-x^2+3)

Combine like terms:

T=(8x^2-x^2)+(-5x+7x)+(-2+3)

Compute. Hence, the total length of the two sides are:

T=7x^2+2x+1

Part B)

To find the length of the third side, we will subtract the length of the T sides from the perimeter. So:

L_{3}=P-T

Substitute:

L_3=(4x^3-3x^2+2x-6)-(7x^2+2x+1)

First, distribute the negative:

L_3=(4x^3-3x^2+2x-6)+(-7x^2-2x-1)

Combine like terms:

L_3=(4x^3)+(-3x^2-7x^2)+(2x-2x)+(-6-1)

Compute. Hence, the third side is:

L_3=4x^3-10x^2-7

Part C)

Yes, Part A and Part B indeed show that polynomials are closed under addition and subtraction.

In Part A, when we added, the variables stayed the same and the result is a polynomial.

In Part B, when we subtracted, the variables stayed the same and the result is a polynomial.

Hence, polynomials are closed under addition and subtraction.

ansver
Answer from: Quest

the answer is d. 75%

ansver
Answer from: Quest

2: 10

step-by-step explanation:

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The lengths of two sides of a triangle are shown. Side 1: 8x2 − 5x − 2

Side 2: 7x − x2...

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