If a sample of 6 keyboards is randomly selected, what is the probability that at least 5 of these will have a mechanical defect

0.1978 is the probability that at least 5 keyboards will have mechanical defect.

Step-by-step explanation:

Solution:

Given:

A repair facility has 25 failed keyboards.

10 keyboards have electrical defect.

15 of which have mechanical defect.

Randomly selected keyboard= 6

The set of A is the set of keyboards with electrical defect.

And  the set of B is set of keyboards with mechanical defect.

N(A U B) = n (A) + n(B) – n (A ∩B)

Probability of at least 5 will have mechanical defect is:

                              = p(  5 mechanical defect  U 6 mechanical defect)

                              = p(5 mechanical defect  ) + p(6 mechanical defect)

                                =(15 C 5 x 10 C1 + 15 C6 X 10C0) / 25 C6

                                = 3003 X 10 / 177100 + 5005 X 1 / 177100

                                = 30030 + 5005 / 177100

                               = 35035 / 177100

                              = 0.1978

0.1978 is the probability that at least 5 keyboards will have mechanical defect.

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step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180