What is an equation in point-slope form of the line that passes through (-7, 1) and (-3, 9)?

y - y1 = m(x - x1)

m = Gradient

m = y - y1 / x - x1

Where:

(-7, 1) = (x, y)

(-3,  9) = (x1, y1)

m = (1 - 9) /( -7 + 3)

m = -8/- 4

m = 2

Inputing this into our point slope form equation : y - y1 = m(x - x1)

We have:

y - 9 = 2(x + 3)

Therefore, Option D is the correct option

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writing the linear equation can be used by any any of those coordinates that are given

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form