Mathematics, 24.09.2020 03:01 sergun252005

Point J is on line segment IK. Given JK 2x – 1, IK = 3x + 2, and IJ = 3x – 5, determine the numerical length of JK.

Answers

JK = 7

Step-by-step explanation:

Point J is on line segment IK.

$\therefore JK + IJ = IK\\\therefore 2x-1 + 3x - 5 = 3x + 2\\\therefore 5x - 6 = 3x + 2\\\therefore 5x - 3x = 2 + 6\\\therefore 2x = 8 \\ \therefore x = \frac{8}{2} \\ \therefore x = 4 \\ \\ JK = 2x - 1 = 2 \times 4 - 1 = 8 - 1 \\ \huge \red{ \boxed{JK = 7}}$

Answer from: Quest

answer: idk

step-by-step explanation:

Answer from: Quest

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

$-4x^4$

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

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Point J is on line segment IK. Given JK 2x – 1, IK = 3x + 2, and IJ = 3x – 5, determine the numeric...