Mathematics, 19.09.2020 01:01 donnafranks2003

Factorise 9(a+b)^2 + (a+b) -8

Answers

Answer from: leleee10

(9a+9b-8)(a+b+1)

Step-by-step explanation:

9(a+b)^2 + (a+b)-8

Expand (a+b)^2

9(a^2+2ab+b^2)+a+b-8

9a^2+18ab+9b^2+a+b-8

Now it is time to think.

Once

$9a^2=9a \cdot a$

$9b^2=9b \cdot b$

18ab=9ab+9ab

$-8=-8 \cdot 1$

We can get something in the format

$(9a+9b-8)(\text{some expression here})$

From the conclusions above,

(9a+9b-8)(a+b+1)

Answer from: Quest

idk

step-by-step explanation:

Answer from: Quest

Ithink it is 52

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