Cheryl has now been lifted to a platform. Again, Daryl throws a ball from a height of 6 ft with an initial vertical velocity of 24 ft/s. At the same time, Cheryl throws the ball she caught earlier. She throws her ball from a height of 24 ft with an initial vertical velocity of 6 ft/s so that it hits Daryl's ball. t = time, in seconds, since the balls were thrown h = height, in feet, above the ground Projectile motion formula: h = −16t2 + vt + h0 Which system of equations models this situation correctly?

h = -16t2 + 24t + 6

         h = -16t2 + 6t + 24

Step-by-step explanation:

i got it right

hope this helps in some way

The answer is h=-16t^2+24t+6

Step-by-step explanation:

got it right!

how am i supposed to answer

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).