Mathematics, 10.06.2020 22:57 PBWaffles4864
Find five consecutive integers such that the sum of the first and 5 times the third is equal to 41 less than 3 times the sum of the second fourth and fifth
Answer from: bougiehairstudios
see below
Step-by-step explanation:
We'll cal the first integer x and then the rest of them will be x + 1, x + 2, x + 3 and x + 4. We can write x + 5(x + 2) = 3(x + 1 + x + 3 + x + 4) - 41.
x + 5x + 10 = 3(3x + 8) - 41
6x + 10 = 9x + 24 - 41
6x + 10 = 9x - 17
3x = 27
x = 9
The numbers are 9, 10, 11, 12, 13.
Answer from: Quest
The answer is
Answer from: Quest
24
step-by-step explanation:
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Find five consecutive integers such that the sum of the first and 5 times the third is equal to 41 l...
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