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Mathematics, 25.04.2020 02:14 joeylozier15

Polygon c has an area of 40 square units. Kennan drew a scaled version of polygon c using a scale factor of one half and labeled it polygon d what is the area of polygon d

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ansver
Answer from: Quest

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

 

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

ansver
Answer from: Quest

d. 8

step-by-step explanation:

the given radical expression is:

\sqrt{16}\times \sqrt{4}

we can rewrite this as:

(16)^{\frac{1}{2}\times (4)^{\frac{1}{2}

we express as square numbers to get;

(4^2)^{\frac{1}{2}\times (2^2)^{\frac{1}{2}

the exponents will now cancel out to give.

4\times2=8

the correct answer is d

What is the value of the radical expression shown below
ansver
Answer from: Quest

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

ansver
Answer from: Quest

step-by-step explanation:

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