Please help ASAP
Questions 1 and 2 plz
Take the sequence in 1a
The 10th term is 31
The 20th is 61
If you wanted to find these by continuing the series, you'd have to add 3 to the last number in the series, then 3 more, then 3 more, until you reach the 20th term. By this point, you will have added 3 to the first term 19 times. That's where the formula comes from. So here,
a = 4, the first term
n = 20, the number of the term we need
d = 3, how much we're adding each time between one term and the next
Then, to get the 20th term,
4 + (20 - 1) • 3 = 4 + (19 • 3) = 4 + 57 = 61
Answers
The 10th and 20th terms of each sequences are
a. 31; 61
b. 48; 98
c. 47; 97
(in c, you're adding the same d as in the sequence above, but your first term is one unit less)
d. -25; -75
(same thing as before, but now, d is negative)
e. 11.5; 16.5
(with d=1/2 or 0.5)
f. 6+1/2; 8+1/2
Use these to check your answers after applying the formula, but know that I calculated on the fly and didn't check these.
infinitely many solutions
step-by-step explanation:
we have been given the equation;
2(2x + 3) = -4 + 2(2x + 5)
we need to determine the value of x.
2(2x + 3), we expand this expression to obtain 4x + 6
similarly 2(2x + 5) will become 4x + 10
now we have;
4x + 6 = -4 + 4x + 10
4x + 6 = 4x + 10 - 4
4x + 6 = 4x + 6
the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;
y = 4x + 6
consequently, we shall have infinitely many solutions
answer:
c 60% on edg
Questions 1 and 2 plz
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