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Mathematics, 28.03.2020 03:18 jaydenromero31

Mikaela places a frame around a print that measures 10 inches by 10 inches. The area of just the frame itself is 69 square inches. What is the width (x) of the frame

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Answer from: nya6557

1.5 inches.

Step-by-step explanation:

Let x represent width of the frame.

We have been given that Mikaela places a frame around a print that measures 10 inches by 10 inches. The area of just the frame itself is 69 square inches.

The area of the print would be 10\times 10=100 square inches.

The side of frame with print would be 10+x+x=10+2x because the width will be on both sides.

Area of side of frame with print would be (10+2x)^2.

Area of the frame will be equal to area of side of frame with print minus area of print.

We can represent this information in an equation as:

69=(10+2x)^2-100

Let us solve for x.

69+100=(10+2x)^2-100+100

169=(10+2x)^2

(10+2x)^2=169

Take square root of both sides:

\sqrt{(10+2x)^2}=\pm\sqrt{169}

10+2x=\pm 13

10+2x=- 13\text{ (or) } 10+2x=13

2x=- 23\text{ (or) } 2x=3

x=-\frac{ 23}{2}\text{ (or) } x=\frac{3}{2}

x=-11.5\text{ (or) } x=1.5

Since width cannot be negative, therefore, width of the frame is 1.5 inches.

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Answer from: Quest

correct answer:

a + bi

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Answer from: Quest

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