Mathematics, 02.10.2019 17:00 emanuelmorales1515

Triangle abc is an isosceles triangle in which ab = ac. what is the perimeter of △abc?
5 + square root of 10 units

3x square root of units

10 + square root of 10 units

15 units

Triangle abc is an isosceles triangle in which ab = ac. what is the perimeter of △abc? 5 + sq

Answers

perimeter = 10 + √10 units

Explanation:
First, we will need to get the length of each line using the distance formula which is as follows:
distance = $\sqrt{( x_{2}- x_{1} )^2 + ( y_{2} - y_{1})^2 }$

1- length of AB:
AB = $\sqrt{(-1--1)^2+(1-6)^2}$ = 5 units

2- length of AC
length of AC is the same as AB = 5 units

3- length of BC:
BC = $\sqrt{(2--1)^2+(2-1)^2}$ = √10 units

Now, we can get the perimeter by adding the side lengths as follows:
perimeter = 5 + 5 + √10
perimeter = 10 + √10 units

Hope this helps :)

Answer from: Quest

Ais the correct answer

Answer from: Quest

The decimal expansion would be .27 repeated

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Triangle abc is an isosceles triangle in which ab = ac. what is the perimeter of △abc?
5 + sq...