The assessed value of Patty's residential property was $200,000 in 2004. In 2006, the
assessed...
Mathematics, 02.03.2020 05:34 ziar7176
The assessed value of Patty's residential property was $200,000 in 2004. In 2006, the
assessed value increased to $225,000. The property tax rate in both years was 1.2 percent.
Patty earned $60,000 each year.
a) Determine Patty's property taxes for 2004 by calculating 1.2 percent of $200,000 (multiply by 0.012), an
determine her taxes for 2006 by calculating 1.2 percent of $225,000. Subtract the 2004 tax figure from the
amount. How much more did Patty have to pay for her property tax in 2006 than in 2004?
b) You can calculate the percentage of Patty's income that she paid in property taxes with simple math. For
instance, in 2004, Patty paid $2,400 in property taxes. Divide that number by her income, $60,000, and you
0.04. or 4 percent. What percentage of her income did Patty pay in property taxes in 2006?
Answer from: lilwon9933
$ 1,965,334
Step-by-step explanation:
Annual sales of company in 1999 = $ 1,200,000
Geometric mean growth rate = 10.37 % = 0.1037
In order to forecast we have to use the concept of Geometric sequence. The annual sales of company in 1999 constitute the first term of the sequence, so:
The growth rate is 10.37% more, this means compared to previous year the growth factor will be
r =1 + 0.1037 = 1.1037
We have to forecast the sales in 2004 which will be the 6th term of the sequence with 1999 being the first term. The general formula for n-th term of the sequence is given as:
So, for 6th term or the year 2004, the forecast will be:
Thus, the forecasted sales for 2004 are $ 1,965,334
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