Mathematics, 12.02.2020 21:02 mojr1000

A student earned grades of 79, 74, and 73 on her three regular exams. She earned a grade of 66 on the final exam and 88 on her course project. Her combined homework grade was 93. Each of the three regular tests counts for 12% of the overall grade, the final exam counts for 17%, the project counts for 10%, and homework counts for 37%. What is her weighted mean grade? Round your answer to two decimal places.

Answers

Answer from: daniellopez18

The weighted mean grade is 78.62

Step-by-step explanation:

We are given the following in the question:

Regular exam score = 79, 74, and 73

Weightage of regular exam = 12%

Final exam grade = 66

Weightage of final exams = 17%

Course project grade = 88

Weightage of project = 10%

Homework grade = 93

Weightage of homework = 37%

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

Mean of regular exam scores =

$Mean =\displaystyle\frac{226}{3} = 75.33$

Weighted mean grade

$w = \dfrac{\sum wx}{\sum w}$

$\displaystyle\sum wx =\displaystyle\frac{12}{100}\times 75.33 + \frac{17}{100}\times 66 + \frac{10}{100}\times 88 + \frac{33}{100}\times 93\\\\\displaystyle\sum wx = 59.75\\\\\sum w = 0.12 + 0.17 + 0.10 + 0.37 = 0.76\\\\w = \frac{59.75}{0.76} = 78.62$

The weighted mean grade is 78.62

Answer from: Quest

i believe the answer is letter c) 8

step-by-step explanation:

Answer from: Quest

4should be the last one n=4

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A student earned grades of 79, 74, and 73 on her three regular exams. She earned a grade of 66 on th...