Mathematics, 12.11.2019 04:31 mathbrain58

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an air force plane left nairobi and flew west at an average speed of 159 mph. a cargo plane left sometime later flying in the same direction at an average speed of 207 mph. after flying for 5.3 hours the cargo plane caught up with the air force plane. find the number of hours the air force plane flew before the cargo plane caught up.
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Answers

Answer from: th483

The air force plane travelled for a total of 6.9 hours.

SOLUTION:

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, $\text { distance travelled }=\text { speed } \times \text { time }$

For air force plane $\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }$

$\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }$

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, $159 \times \text { time taken by air force plane }=207 \times 5.3$

$\Rightarrow =\frac{207 \times 5.3}{159}$

$\Rightarrow =\frac{1097.1}{159}$

Time taken by air force plane = 6.9 hrs

Answer from: Quest

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒ $x\frac{60}{100}=45$

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

$\frac{x(.6)}{(.6)}= \frac{45}{(.6)}$

⇒ x = 75

therefore 75 tickets have been sold so far.

Answer from: Quest

$</p><p>4^{(-3)^{2}}=4^9=\boxed{429}</p><p>$

hope this .

r3t40

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