Mathematics, 12.11.2019 01:31 neariah24

12 a box contains 5 blue balls, 3 black balls and 2
red bals of the same size. a ball is selected at
random from the box and then replaced. a second
ball is then selected find the probability of
obtaining (a) two red balls. (b) two blue balls or
w black basic) one black ball and one red
palany order

Answers

R= red, B=blue, Bl=black
(a) p(R) X p(R) = 2/10 X 2/10 = 4/100 = 1/25

(b) p(B) X p(B) = 5/10 X 5/10 = 25/100
+ +
p(Bl) X p(R) =3/10 X 2/10 = 6/100 = 37/100
+ +
p(R) X p(Bl) =2/10 X 3/10 = 6/100

Answer from: Quest

200 miles.45 x 3 (charge per day times days)135$205$ - 135$ = 70$0.35x = 70divide both sides by 0.35200

Answer from: Quest

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

Find the value of y. round to the nearest tenth.

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12 a box contains 5 blue balls, 3 black balls and 2
red bals of the same size. a ball is select...