Given: pq= tq, uq: qs
prove: ps tu
reasons
statements
1. pq= to, uq= os
2. pq = tq, uq = qs
3. pq+ qs = ps; tq + qu = tu
4. tq + qs = ps
5. tq + qs = tu
6. ps = tu
7. ps = tu
1. given
2. reflexive ž
3. addition poe
4. seament addition post
5. seament addition post
6. u
7. definition of congroencel
gina wilson (all things algebra), 2014

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