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Mathematics, 24.06.2019 13:30 chloedfite2978

Find the equation of a circle with center (6,-2) and radius 12

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Answer from: savanna39

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{6}{ h},\stackrel{-2}{ k})\qquad \qquad radius=\stackrel{12}{ r} \\[2em] [x-6]^2+[y-(-2)]^2=12^2\implies (x-6)^2+(y+2)^2=144

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Answer from: Quest

proportions are fractions that equal to each other. so if two fractions are the same, they are proportional.

let's check the answers to see if they are proportional.

question a is not proportional because you can't turn 1.5/3 to 3/9. if you try to multiply 1.5/3 by 2 or 3, you wont get 3/9. it's impossible to make the fractions the same.

question b is not proportional because you can't turn 22/33 to 4/6. 33 can't go into 6.

question c is proportional because when you multiply 2 and 3 by 71, you would get 142/213, and those fractions equal to each other

question d is proportional because when you divide 14 and 7 by 2, you would end up with 7/3.5, and those fractions equal to each other.

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Answer from: Quest

i'll be glad to : )

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Find the equation of a circle with center (6,-2) and radius 12...