Mathematics, 26.06.2019 17:30 homework2358
Find the value of the monomial 2m^2np^3 for: m=3, n=1, p=2 find the value of the monomial 2m^2np^3 for: m=0.5, n=4, p=1 rewrite as a monomial in standard form: (− 2/3 x^2y)^3*(− 3/4 xy^2)^2
Answer from: miacervenka
1442-1/6 x⁸y⁷
Step-by-step explanation:
For the first two, fill in the given values and do the arithmetic.
... 2(3²)(1)(2³) = 2×9×8 = 144
... 2(0.5²)(4)(1³) = 2×(1/4)×4 = 2
_____
The outside exponents are distributed over the inside factors according to the rule:
... (a^b)^c = a^(b·c)
Then the rule ...
... (a^b)(a^c) = a^(b+c)
applies to the product.
... (− 2/3 x²y)³·(− 3/4 xy²)² = (-2/3)³x⁶y³·(-3/4)²x²y⁴
... = (-8/27)(9/16)x⁽⁶⁺²⁾y⁽³⁺⁴⁾
... = -1/6 x⁸y⁷
Answer from: Quest
2
step-by-2step explanation:
Answer from: Quest
the correct answer to your question is a. 4^4
good luck my friend!
hope this !
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have a splendid day < 3 : )
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Find the value of the monomial 2m^2np^3 for: m=3, n=1, p=2 find the value of the monomial 2m^2np^3...
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