Mathematics, 17.07.2019 03:00 skater9919
Can some one me with the questions?
Answer from: jesser9
Notice that x+4 is one of the denominators, and that x(x+4) is the LCD.
x
Thus, mult. by x(x+4), obtaining x^2.
x+4
Next, mult. [ 1/x + 1/(x+4) by x(x+4), obtaining x+4 + x = 2x+4 or 2(x+4)
x^2
Then the simplified fraction becomes
2(x+4)
Generally allows you to post only 1 or 2 questions at a time. I will do #15 as a courtesy to you, but want you to try #16 yourself (or to post it separately).
-4, 2, 8, 14, ... is an arithm. seq. Every new term is equal to the previous term, plus 6: -4+6 = 2; 2+6=8, and so on. Thus: first term is a = -4; common difference is d = 6
a(50) = a(1) + (50-1)(6), or a(50) = -4 + (49)(6) = 290 (answer)
x
Thus, mult. by x(x+4), obtaining x^2.
x+4
Next, mult. [ 1/x + 1/(x+4) by x(x+4), obtaining x+4 + x = 2x+4 or 2(x+4)
x^2
Then the simplified fraction becomes
2(x+4)
Generally allows you to post only 1 or 2 questions at a time. I will do #15 as a courtesy to you, but want you to try #16 yourself (or to post it separately).
-4, 2, 8, 14, ... is an arithm. seq. Every new term is equal to the previous term, plus 6: -4+6 = 2; 2+6=8, and so on. Thus: first term is a = -4; common difference is d = 6
a(50) = a(1) + (50-1)(6), or a(50) = -4 + (49)(6) = 290 (answer)
Answer from: Quest
were is the equation
Answer from: Quest
The answer is why would a teacher ask that
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