Chemistry, 27.05.2021 22:30 ethanyayger
Calculate the number of molecules found in 18 g of CO GAS 2
Answer from: Quest
remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.
Answer from: Quest
Answer is (d)a brainliest would be appreciated
Answer from: Quest
As long as you're breathing, you'll be fine : /p. s. if you aren't breathing, you'll pass out. mark as brainliest.
Answer from: Quest
The question is incomplete. complete question is attached belowanswer: correct answer is option b i.e. solid particles reason: filter paper has small pores, through which smaller particles can pass through. however, solid particles have relatively larger size. hence, they are least likely to pass through.
Chemistry, 23.06.2019 10:30, dreamxette3119
Fill in the blanks for the following statements: the rms speed of the molecules in a sample of h2 gas at 300 k will be times larger than the rms speed of o2 molecules at the same temperature, and the ratio µrms (h2) / µrms (o2) with increasing temperature. a not enough information is given to answer this question b sixteen, will not change c four, will not change d four, will increase e sixteen, will decrease
Answers: 2
Chemistry, 23.06.2019 14:50, aleilyg2005
Use the bond energies provided to estimate δh°rxn for the reaction below. ch3oh(l) + 2 o2(g) → co2(g) + 2 h2o(g) δh°rxn = ? bond bond energy (kj/mol) c-h 414 c-o 360 c=o 799 o=o 498 o-h 464 use the bond energies provided to estimate δh°rxn for the reaction below. ch3oh(l) + 2 o2(g) → co2(g) + 2 h2o(g) δh°rxn = ? bond bond energy (kj/mol) c-h 414 c-o 360 c=o 799 o=o 498 o-h 464 +473 kj +206 kj -392 kj -91 kj -486 kj
Answers: 1
Calculate the number of molecules found in 18 g of CO GAS 2...
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