Chemistry, 24.10.2019 18:43 kenyakids405

In the following combustion reaction of acetylene (c2h2), how many liters of co2 will be produced if 60 liters of o2 is used, given that both gases are at stp? 2c2h2+5o2 2h2o+4co2 the volume of one mole of gas at stp is 22.4 liters. 48 liters 0.02 liters 240 liters 300 liters nextreset

Answers

Answer from: em387p3s1zr

V(O₂)=60 L

V(O₂)/5=V(CO₂)/4

V(CO₂)=4V(O₂)/5

V(CO₂)=4*60/5=48 L

48 liters

Answer from: thomasalmo2014

Answer : The volume of CO_2 produced will be, 48 liters.

Explanation : Given,

Volume of O_2 = 60 L

First we have to calculate the moles of O_2 .

The given balanced chemical reaction is,

$2C_2H_2+5O_2\rightarrow 2H_2O+4CO_2$

From the balanced chemical reaction, we conclude that

As, 22.4 L volume of O_2 present in 1 mole of O_2

So, 60 L volume of O_2 present in $\frac{60}{22.4}=2.68$ mole of O_2

Now we have to calculate the moles of CO_2 .

From the reaction we conclude that,

As, 5 moles of O_2 react to give 4 moles of CO_2

So, 2.68 moles of O_2 react to give $\frac{4}{5}\times 2.68=2.144$ moles of CO_2

Now we have to calculate the volume of CO_2 .

At STP,

As, 1 mole of CO_2 contains 22.4 L volume of CO_2

So, 2.144 mole of CO_2 contains $2.144\times 22.4=48.0L$ volume of CO_2

Therefore, the volume of CO_2 produced will be, 48 liters.

Answer from: Quest

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Answer from: Quest

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In the following combustion reaction of acetylene (c2h2), how many liters of co2 will be produced if...