Chemistry, 02.12.2019 04:31 ogiebert

Calculate the heat change in calories for condensation of 20.0 g of steam at 100∘c.

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Answer from: jake9919

The latent heat of vaporization of steam is equal to its latent heat of condensation. The heat released is given by:
Q = ml
Q = 20 x 2257 joules/gram
Q = 45.14 kJ of heat is removed from the steam

1 calorie = 4.184 kJ
45.14 kJ = 10.8 cal of energy

The energy removed is 10.8 calories

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Calculate the heat change in calories for condensation of 20.0 g of steam at 100∘c....