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Chemistry, 29.01.2020 14:54 OliTepley5966

What mass of no2 can be produced from 3.56x10^22 molecules of oxygen? the equation with it is 4nh3+> 4no2+6h2o

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Answer from: jr116641
Moles of O2 = 3.56x10^22/ 32 = 1.1125x 10^21

Maximum moles of NO2 producible = (1.1125x10^21/7) x 4 =  6.3571 x 10^20

Mass of 1 mole of NO2 = 14+32= 46

Therefore mass that can be produced= (6.3571x10^20) * 46 = 2.924x10^22 g
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Answer from: Quest

\frac{239}{94}pu+\frac{1}{0}n ====> \frac{y}{z}x+\frac{134}{54}xe+3\frac{1}{0}

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

\frac{103}{40}x=\frac{103}{40}zr

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Answer from: Quest

answerlinnaeus;

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What mass of no2 can be produced from 3.56x10^22 molecules of oxygen? the equation with it is 4nh3+...

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