Chemistry, 31.10.2019 04:31 officialalex8635

What is the molarity of a 1.5l solution with 25 g of nacl?

Answers

Molar mass NaCl = 58.44 g/mol

number of moles

1 mole 58.44 g
? moles 25 g

25 x 1 / 58.44 => 0.4277 moles

Therefore:

M = n / V

M =0.4277 / 1.5

M = 0.285 mol/L

Answer from: Quest

Hairy thick gross thing? idk

Answer from: Quest

the dissociation of nickel hydroxide is follows:

$ni(oh)_2 > ni^2^+ + 2 oh^-$

$ksp for no(oh)2 = 5.5 * 10^-^1^6$

$5.5 * 10^-^1^6 = s * (2 s)^2 = 4 s^3$

$s^3 = 137.5 * 10^-^1^8$

$s = 5.14 * 10^-^6 = [oh^-]$

the concentration of hydroxide ion is

$5.14 * 10^-^6 = [oh^-]$

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

$k = [ ni^2^+] * [oh^-]^2$

$6.1 * 10^-^1^6 = [ ni^2] * [5.14 * 10^-^6]^2$

$[ ni^2^+] = 0.23 * 10^-^4 mol /l$

thus, concentration of ni is 0.23 * 10^-^4 mol /l

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