Chemistry, 18.04.2020 03:11 hasshh

At 25 celsius, 1.00 ,ole of O2 was found to occupy a volume of 12.5 L at a pressure of 198 kPa. What value of the gas constant in L times kPa divided by mol Times K

Answers

Answer from: anasfis35ovmbff

$R=8.301\frac{L*kPa}{mol*K}$

Explanation:

Hello,

In this case, assuming oxygen as an ideal gas, it is described by:

PV=nRT

Whereas the gas constant R is required, therefore, it is computed as shown below:

$R=\frac{PV}{nT} =\frac{198kPa*12.5L}{1.00mol*(25+273.15)K} \\\\R=8.301\frac{L*kPa}{mol*K}$

Best regards.

Answer from: Quest

A.(nh4)(2co3)is the correct answer

Answer from: Quest

Your question is not clear but if you can explain yourself i would be glad to . just trying to : ))

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At 25 celsius, 1.00 ,ole of O2 was found to occupy a volume of 12.5 L at a pressure of 198 kPa. What...