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Chemistry, 11.09.2019 04:20 kilofox51

Consider the formation of nitryl fluoride: 2no2(g)+f2(g)⇌2no2f(g) the reaction is first order in f2 and second order overall. what is the rate law? view available hint(s) consider the formation of nitryl fluoride: the reaction is first order in and second order overall. what is the rate law? rate=k[no2]2[f2]2 rate=k[no2][f2]2 rate=k[f2] rate=k[no2] rate=k[no2][f2] rate=k[no2]2[f2]

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Answer from: richdakid26

Rate = k[NO_{2}][F_{2}]

Explanation:

Two reactants are present in this reaction which are NO_{2}and F_{2}We know overall order of a reaction is summation of individual order with respect to reactants present in rate law equation.Here, overall order of reaction is 2 including first order with respect to F_{2}So, rate of reaction should also be first order with respect to another reactant i.e. first order with respect to NO_{2}So, rate law: rate = k[NO_{2}][F_{2}]
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Answer from: Quest

a non redox reaction occurs when there is not a transfer of electrons. for redox reactions, which are reduction-oxidation reactions, a change in the oxidation number occurs. elements that are reduced gain electrons, and elements that are oxidized lose electrons.

explanation:

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Answer from: Quest
Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

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Consider the formation of nitryl fluoride: 2no2(g)+f2(g)⇌2no2f(g) the reaction is first order in f2...